ν‹°μŠ€ν† λ¦¬μ±Œλ¦°μ§€

URL을 λΈŒλΌμš°μ €μ— μž…λ ₯ν–ˆμ„ λ•Œ μΌμ–΄λ‚˜λŠ” 과정을 λ”₯ν•˜κ²Œ μ•Œμ•„λ³΄μž! 1. URL νŒŒμ‹±λΈŒλΌμš°μ €λŠ” μž…λ ₯된 URL을 ν•΄μ„ν•˜μ—¬ ν”„λ‘œν† μ½œ / 도메인 λ„€μž„ / 경둜 / 쿼리 λ§€κ°œλ³€μˆ˜ λ“±μœΌλ‘œ λΆ„λ¦¬ν•œλ‹€.λΈŒλΌμš°μ €λŠ” URLμ—μ„œ example.com μ΄λΌλŠ” 도메인 λ„€μž„μ„ μΆ”μΆœν•˜κ³  이λ₯Ό 톡해 DNS 쿼리가 μ‹œμž‘λœλ‹€.  2. DNS (Domain Name System) 쑰회Domain Name은 μ‚¬λžŒμ΄ μ΄ν•΄ν•˜κΈ° μ‰¬μš΄ μ£Όμ†Œμ§€λ§Œ, μ»΄ν“¨ν„°λŠ” IP μ£Όμ†Œλ₯Ό 톡해 ν†΅μ‹ ν•œλ‹€.DNSλŠ” 도메인 λ„€μž„μ„ IP둜 λ³€ν™˜ν•˜κΈ° μœ„ν•΄ μ‘΄μž¬ν•œλ‹€. μ›Ή λΈŒλΌμš°μ €λŠ” DNS μ„œλ²„μ— κ²€μƒ‰ν•˜κΈ° 전에 μΊμ‹±λœ DNS 기둝을 λ¨Όμ € ν™•μΈν•œλ‹€.μΊμ‹œμ— ν•΄λ‹Ή 정보가 μ—†λ‹€λ©΄, λΈŒλΌμš°μ €λŠ” 도메인을 IP μ£Όμ†Œλ‘œ λ³€ν™˜ν•˜κΈ° μœ„ν•΄ DNS μ„œλ²„μ— μš”μ²­μ„ 보낸닀. μ΄ μš”μ²­μ€ μ‚¬μš©μžμ˜ ISP(In..
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.Implement the MinStack class:- MinStack() initializes the stack object.- void push(int val) pushes the element val onto the stack.- void pop() removes the element on the top of the stack.- int top() gets the top element of the stack.- int getMin() retrieves the minimum element in the stack.You must i..
Determine if a 9 x 9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:Each row must contain the digits 1-9 without repetition.Each column must contain the digits 1-9 without repetition.Each of the nine 3 x 3 sub-boxes of the grid must contain the digits 1-9 without repetition.Note:A Sudoku board (partially filled) could be valid but is not necess..
Given an unsorted array of integers nums, return the length of the longest consecutive elements sequence.You must write an algorithm that runs in O(n) time.longest consecutive sequenceλ₯Ό μ°ΎλŠ” 문제! O(n) μ•ˆμœΌλ‘œ ν’€μ–΄μ•Ό ν•œλ‹€.μ£Όμ˜ν•  점은 constraints에 nums의 lengthκ°€ 0λΆ€ν„° κ°€λŠ₯ν•˜λ‹€λŠ” 것  Hash Set을 μ΄μš©ν•œ 풀이class Solution: def longestConsecutive(self, nums: List[int]) -> int: numSet = set(nums) longest = 0 f..
A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. Alphanumeric characters include letters and numbers.Given a string s, return true if it is a palindrome, or false otherwise.μœ νš¨ν•œ palindrome(회문) κ²€μ‚¬ν•˜λŠ” λ©”μ„œλ“œ κ΅¬ν˜„ν•˜κΈ°! ν’€μ΄1: Reverse Stringclass Solution: def isPalindrome(self, s:..
Given a string s containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.An input string is valid if:Open brackets must be closed by the same type of brackets.Open brackets must be closed in the correct order.Every close bracket has a corresponding open bracket of the same type.κ΄„ν˜Έκ°€ μ˜¬λ°”λ₯΄κ²Œ μ§μ§€μ–΄μ‘ŒλŠ”μ§€ ν™•μΈν•˜λŠ” 문제! ν’€μ΄1: Stack 이용class Solution: def isValid(sel..
μ œλ„€λ¦­(Generic)μ΄λž€?Cλ‚˜ μžλ°” 같은 정적 μ–Έμ–΄μ—μ„œ λ‹€μ–‘ν•œ νƒ€μž… 간에 μž¬μ‚¬μš©μ„±μ„ 높이기 μœ„ν•΄ μ‚¬μš©ν•˜λŠ” 문법이닀. νƒ€μž…μŠ€ν¬λ¦½νŠΈλ„ 정적 νƒ€μž…μ„ κ°€μ§€λ―€λ‘œ μ œλ„€λ¦­ 문법을 μ§€μ›ν•œλ‹€.μ œλ„€λ¦­μ˜ 사전적 μ˜λ―ΈλŠ” 일반적인 것(general)을 λœ»ν•˜λŠ”λ°, νƒ€μž…μŠ€ν¬λ¦½νŠΈμ˜ μ œλ„€λ¦­λ„ 이와 λΉ„μŠ·ν•˜κ²Œ 'μΌλ°˜ν™”λœ 데이터' νƒ€μž…μ΄λΌ λ³Ό 수 μžˆλ‹€.μ œλ„€λ¦­: ν•¨μˆ˜, νƒ€μž…, 클래슀 λ“±μ—μ„œ λ‚΄λΆ€μ μœΌλ‘œ μ‚¬μš©ν•  νƒ€μž…μ„ 미리 정해두지 μ•Šκ³  νƒ€μž… λ³€μˆ˜λ₯Ό μ‚¬μš©ν•΄μ„œ ν•΄λ‹Ή μœ„μΉ˜λ₯Ό λΉ„μ›Œ λ‘” λ‹€μŒμ—, μ‹€μ œλ‘œ κ·Έ 값을 μ‚¬μš©ν•  λ•Œ μ™ΈλΆ€μ—μ„œ νƒ€μž… λ³€μˆ˜ μžλ¦¬μ— νƒ€μž…μ„ μ§€μ •ν•˜μ—¬ μ‚¬μš©ν•˜λŠ” 방식-> μ΄λ ‡κ²Œ ν•˜λ©΄ ν•¨μˆ˜, νƒ€μž…, 클래슀 λ“± μ—¬λŸ¬ νƒ€μž…μ— λŒ€ν•΄ ν•˜λ‚˜ν•˜λ‚˜ λ”°λ‘œ μ •μ˜ν•˜μ§€ μ•Šμ•„λ„ 되기 λ•Œλ¬Έμ— μž¬μ‚¬μš©μ„±μ΄ 크게 ν–₯μƒλœλ‹€.νƒ€μž… λ³€μˆ˜λŠ” 일반적으둜 와 같이 κΊΎμ‡ κ΄„ν˜Έ 내뢀에..
Given an integer array nums and an integer k, return the k most frequent elements. You may return the answer in any order.λΉˆλ„μˆ˜κ°€ 높은 μˆœμ„œλŒ€λ‘œ, μƒμœ„ k개의 elementsλ₯Ό 좜λ ₯ν•˜λŠ” λ¬Έμ œλ‹€. ν’€μ΄ 1class Solution: def topKFrequent(self, nums: List[int], k: int) -> List[int]: count = defaultdict(int) for i in nums: count[i] += 1 result = sorted(count, key=count.get, reverse=Tr..
yesolz
'ν‹°μŠ€ν† λ¦¬μ±Œλ¦°μ§€' νƒœκ·Έμ˜ κΈ€ λͺ©λ‘